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12103010133 = 32924797071
BaseRepresentation
bin10110100010110010…
…10100011101010101
31011020110221121200120
423101121110131111
5144241332311013
65320545302153
7605631613554
oct132131243525
934213847616
1012103010133
115150919715
122419334959
1311ab5c0476
1482b593d9b
154ac81c123
hex2d1654755

12103010133 has 12 divisors (see below), whose sum is σ = 16712998848. Its totient is φ = 7790441680.

The previous prime is 12103010131. The next prime is 12103010137. The reversal of 12103010133 is 33101030121.

12103010133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12103010133 - 21 = 12103010131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12103010131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2396013 + ... + 2401058.

It is an arithmetic number, because the mean of its divisors is an integer number (1392749904).

Almost surely, 212103010133 is an apocalyptic number.

It is an amenable number.

12103010133 is a deficient number, since it is larger than the sum of its proper divisors (4609988715).

12103010133 is an equidigital number, since it uses as much as digits as its factorization.

12103010133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4797132 (or 4797103 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12103010133 its reverse (33101030121), we get a palindrome (45204040254).

The spelling of 12103010133 in words is "twelve billion, one hundred three million, ten thousand, one hundred thirty-three".

Divisors: 1 3 29 87 841 2523 4797071 14391213 139115059 417345177 4034336711 12103010133