Base | Representation |
---|---|
bin | 10110100010110010… |
… | …11100100101001010 |
3 | 1011020111000022022202 |
4 | 23101121130211022 |
5 | 144241334342102 |
6 | 5320550120202 |
7 | 605632112552 |
oct | 132131344512 |
9 | 34214008282 |
10 | 12103043402 |
11 | 515094170a |
12 | 2419350062 |
13 | 11ab602658 |
14 | 82b5a2162 |
15 | 4ac826e02 |
hex | 2d165c94a |
12103043402 has 4 divisors (see below), whose sum is σ = 18154565106. Its totient is φ = 6051521700.
The previous prime is 12103043401. The next prime is 12103043419. The reversal of 12103043402 is 20434030121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8251723921 + 3851319481 = 90839^2 + 62059^2 .
It is not an unprimeable number, because it can be changed into a prime (12103043401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3025760849 + ... + 3025760852.
Almost surely, 212103043402 is an apocalyptic number.
12103043402 is a deficient number, since it is larger than the sum of its proper divisors (6051521704).
12103043402 is an equidigital number, since it uses as much as digits as its factorization.
12103043402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6051521703.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 12103043402 its reverse (20434030121), we get a palindrome (32537073523).
The spelling of 12103043402 in words is "twelve billion, one hundred three million, forty-three thousand, four hundred two".
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