Base | Representation |
---|---|
bin | 111000010110111111… |
… | …0111010100000000011 |
3 | 102120101211100001110120 |
4 | 1300231332322200003 |
5 | 3440332310122210 |
6 | 131333424431323 |
7 | 11513151466614 |
oct | 1605576724003 |
9 | 376354301416 |
10 | 121030551555 |
11 | 47368655821 |
12 | 1b558a78543 |
13 | b54a8605a4 |
14 | 5c02167c0b |
15 | 32356be270 |
hex | 1c2dfba803 |
121030551555 has 32 divisors (see below), whose sum is σ = 200571024960. Its totient is φ = 62247682560.
The previous prime is 121030551547. The next prime is 121030551557. The reversal of 121030551555 is 555155030121.
It is not a de Polignac number, because 121030551555 - 23 = 121030551547 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121030551557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 187689 + ... + 526581.
It is an arithmetic number, because the mean of its divisors is an integer number (6267844530).
Almost surely, 2121030551555 is an apocalyptic number.
121030551555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
121030551555 is a deficient number, since it is larger than the sum of its proper divisors (79540473405).
121030551555 is a wasteful number, since it uses less digits than its factorization.
121030551555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 339751.
The product of its (nonzero) digits is 18750, while the sum is 33.
Adding to 121030551555 its reverse (555155030121), we get a palindrome (676185581676).
The spelling of 121030551555 in words is "one hundred twenty-one billion, thirty million, five hundred fifty-one thousand, five hundred fifty-five".
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