Search a number
-
+
1210311313444 = 221132677679897
BaseRepresentation
bin10001100111001100001…
…011010000100000100100
311021201000200021002212101
4101213030023100200210
5124312204144012234
62324002003501444
7153304433264242
oct21471413204044
94251020232771
101210311313444
11427321202542
12176696987884
138a1939345cc
1442817b67792
152173a08e814
hex119cc2d0824

1210311313444 has 12 divisors (see below), whose sum is σ = 2136788558604. Its totient is φ = 599800296704.

The previous prime is 1210311313399. The next prime is 1210311313501. The reversal of 1210311313444 is 4443131130121.

It can be written as a sum of positive squares in 2 ways, for example, as 188416764900 + 1021894548544 = 434070^2 + 1010888^2 .

It is a super-2 number, since 2×12103113134442 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1338839497 + ... + 1338840400.

It is an arithmetic number, because the mean of its divisors is an integer number (178065713217).

Almost surely, 21210311313444 is an apocalyptic number.

It is an amenable number.

1210311313444 is a deficient number, since it is larger than the sum of its proper divisors (926477245160).

1210311313444 is a wasteful number, since it uses less digits than its factorization.

1210311313444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2677680014 (or 2677680012 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1210311313444 its reverse (4443131130121), we get a palindrome (5653442443565).

The spelling of 1210311313444 in words is "one trillion, two hundred ten billion, three hundred eleven million, three hundred thirteen thousand, four hundred forty-four".

Divisors: 1 2 4 113 226 452 2677679897 5355359794 10710719588 302577828361 605155656722 1210311313444