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12103222013 = 15541778793
BaseRepresentation
bin10110100010110100…
…01000001011111101
31011020111100101022222
423101122020023331
5144241411101023
65320554015125
7605633455361
oct132132101375
934214311288
1012103222013
115150a53923
1224194174a5
1311ab665a3c
1482b60b2a1
154ac85ecc8
hex2d16882fd

12103222013 has 4 divisors (see below), whose sum is σ = 12104016348. Its totient is φ = 12102427680.

The previous prime is 12103222009. The next prime is 12103222031. The reversal of 12103222013 is 31022230121.

12103222013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8249543929 + 3853678084 = 90827^2 + 62078^2 .

It is a cyclic number.

It is not a de Polignac number, because 12103222013 - 22 = 12103222009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12103221982 and 12103222000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12103222003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373856 + ... + 404937.

It is an arithmetic number, because the mean of its divisors is an integer number (3026004087).

Almost surely, 212103222013 is an apocalyptic number.

It is an amenable number.

12103222013 is a deficient number, since it is larger than the sum of its proper divisors (794335).

12103222013 is an equidigital number, since it uses as much as digits as its factorization.

12103222013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794334.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12103222013 its reverse (31022230121), we get a palindrome (43125452134).

It can be divided in two parts, 1210 and 3222013, that added together give a palindrome (3223223).

The spelling of 12103222013 in words is "twelve billion, one hundred three million, two hundred twenty-two thousand, thirteen".

Divisors: 1 15541 778793 12103222013