Base | Representation |
---|---|
bin | 1011000000100000011000… |
… | …1101110101101010101001 |
3 | 1120212001210022220012012020 |
4 | 2300020012031311222221 |
5 | 3041300100431143423 |
6 | 41424104525535053 |
7 | 2356302414436323 |
oct | 260100615655251 |
9 | 46761708805166 |
10 | 12103322131113 |
11 | 3946a988a0204 |
12 | 1435856114489 |
13 | 69a45255ca85 |
14 | 2dbb37d3a613 |
15 | 15ec7db304e3 |
hex | b0206375aa9 |
12103322131113 has 8 divisors (see below), whose sum is σ = 16137816878976. Its totient is φ = 8068854402000.
The previous prime is 12103322131099. The next prime is 12103322131193. The reversal of 12103322131113 is 31113122330121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12103322131113 - 25 = 12103322131081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12103322131193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5685258 + ... + 7518563.
It is an arithmetic number, because the mean of its divisors is an integer number (2017227109872).
Almost surely, 212103322131113 is an apocalyptic number.
It is an amenable number.
12103322131113 is a deficient number, since it is larger than the sum of its proper divisors (4034494747863).
12103322131113 is a wasteful number, since it uses less digits than its factorization.
12103322131113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13509375.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 12103322131113 its reverse (31113122330121), we get a palindrome (43216444461234).
The spelling of 12103322131113 in words is "twelve trillion, one hundred three billion, three hundred twenty-two million, one hundred thirty-one thousand, one hundred thirteen".
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