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12104000234 = 26052000117
BaseRepresentation
bin10110100010111010…
…00110001011101010
31011020112210220211222
423101131012023222
5144242111001414
65321022422042
7605643206264
oct132135061352
934215726758
1012104000234
115151435587
122419731922
1311ab879021
1482b770b34
154ac96568e
hex2d17462ea

12104000234 has 4 divisors (see below), whose sum is σ = 18156000354. Its totient is φ = 6052000116.

The previous prime is 12104000191. The next prime is 12104000257. The reversal of 12104000234 is 43200040121.

12104000234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43200040121 = 76171434303.

It can be written as a sum of positive squares in only one way, i.e., 12101100025 + 2900209 = 110005^2 + 1703^2 .

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3026000057 + ... + 3026000060.

Almost surely, 212104000234 is an apocalyptic number.

12104000234 is a deficient number, since it is larger than the sum of its proper divisors (6052000120).

12104000234 is an equidigital number, since it uses as much as digits as its factorization.

12104000234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6052000119.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 12104000234 its reverse (43200040121), we get a palindrome (55304040355).

The spelling of 12104000234 in words is "twelve billion, one hundred four million, two hundred thirty-four", and thus it is an aban number.

Divisors: 1 2 6052000117 12104000234