Base | Representation |
---|---|
bin | 111000010111010001… |
… | …1011101110000001100 |
3 | 102120102111100211220210 |
4 | 1300232203131300030 |
5 | 3440342233230012 |
6 | 131334410042420 |
7 | 11513326104342 |
oct | 1605643356014 |
9 | 376374324823 |
10 | 121040133132 |
11 | 47372aaa586 |
12 | 1b560119410 |
13 | b54c836869 |
14 | 5c0353d992 |
15 | 323646323c |
hex | 1c2e8ddc0c |
121040133132 has 48 divisors (see below), whose sum is σ = 294804195840. Its totient is φ = 38579701248.
The previous prime is 121040133101. The next prime is 121040133143. The reversal of 121040133132 is 231331040121.
It is a super-2 number, since 2×1210401331322 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121040133099 and 121040133108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 778588 + ... + 921020.
It is an arithmetic number, because the mean of its divisors is an integer number (6141754080).
Almost surely, 2121040133132 is an apocalyptic number.
121040133132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
121040133132 is an abundant number, since it is smaller than the sum of its proper divisors (173764062708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121040133132 is a wasteful number, since it uses less digits than its factorization.
121040133132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145542 (or 145540 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 121040133132 its reverse (231331040121), we get a palindrome (352371173253).
The spelling of 121040133132 in words is "one hundred twenty-one billion, forty million, one hundred thirty-three thousand, one hundred thirty-two".
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