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12104113 = 74340213
BaseRepresentation
bin101110001011…
…000110110001
3211202221201111
4232023012301
511044312423
61111233321
7204611650
oct56130661
924687644
1012104113
116917aaa
124078841
13267a4c8
141871197
1510e160d
hexb8b1b1

12104113 has 8 divisors (see below), whose sum is σ = 14155328. Its totient is φ = 10133424.

The previous prime is 12104111. The next prime is 12104177. The reversal of 12104113 is 31140121.

12104113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12104113 - 21 = 12104111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12104093 and 12104102.

It is not an unprimeable number, because it can be changed into a prime (12104111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19806 + ... + 20407.

It is an arithmetic number, because the mean of its divisors is an integer number (1769416).

Almost surely, 212104113 is an apocalyptic number.

It is an amenable number.

12104113 is a deficient number, since it is larger than the sum of its proper divisors (2051215).

12104113 is an equidigital number, since it uses as much as digits as its factorization.

12104113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40263.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 12104113 is about 3479.0965781363. The cubic root of 12104113 is about 229.6030519268.

Adding to 12104113 its reverse (31140121), we get a palindrome (43244234).

The spelling of 12104113 in words is "twelve million, one hundred four thousand, one hundred thirteen".

Divisors: 1 7 43 301 40213 281491 1729159 12104113