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12104330000 = 24547192479
BaseRepresentation
bin10110100010111100…
…10110101100010000
31011020120102200012112
423101132112230100
5144242202030000
65321033444452
7605646051560
oct132136265420
934216380175
1012104330000
115151640314
122419870728
1311ab963159
1482b818da0
154ac9cd235
hex2d1796b10

12104330000 has 300 divisors, whose sum is σ = 35421661440. Its totient is φ = 3923424000.

The previous prime is 12104329997. The next prime is 12104330003. The reversal of 12104330000 is 3340121.

It is an interprime number because it is at equal distance from previous prime (12104329997) and next prime (12104330003).

It is a Harshad number since it is a multiple of its sum of digits (14).

It is not an unprimeable number, because it can be changed into a prime (12104330003) by changing a digit.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 25269761 + ... + 25270239.

Almost surely, 212104330000 is an apocalyptic number.

12104330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12104330000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17710830720).

12104330000 is an abundant number, since it is smaller than the sum of its proper divisors (23317331440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12104330000 is an equidigital number, since it uses as much as digits as its factorization.

12104330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 552 (or 512 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 12104330000 its reverse (3340121), we get a palindrome (12107670121).

The spelling of 12104330000 in words is "twelve billion, one hundred four million, three hundred thirty thousand".