Base | Representation |
---|---|
bin | 10110100010111100… |
… | …11001101001100010 |
3 | 1011020120110021211012 |
4 | 23101132121221202 |
5 | 144242202421424 |
6 | 5321034020522 |
7 | 605646132104 |
oct | 132136315142 |
9 | 34216407735 |
10 | 12104342114 |
11 | 5151649427 |
12 | 2419877742 |
13 | 11ab968817 |
14 | 82b81d574 |
15 | 4ac9d1b0e |
hex | 2d1799a62 |
12104342114 has 4 divisors (see below), whose sum is σ = 18156513174. Its totient is φ = 6052171056.
The previous prime is 12104342093. The next prime is 12104342149. The reversal of 12104342114 is 41124340121.
12104342114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41124340121 = 12211 ⋅3367811.
It can be written as a sum of positive squares in only one way, i.e., 12070318225 + 34023889 = 109865^2 + 5833^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 12104342114.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3026085527 + ... + 3026085530.
Almost surely, 212104342114 is an apocalyptic number.
12104342114 is a deficient number, since it is larger than the sum of its proper divisors (6052171060).
12104342114 is an equidigital number, since it uses as much as digits as its factorization.
12104342114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6052171059.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12104342114 its reverse (41124340121), we get a palindrome (53228682235).
The spelling of 12104342114 in words is "twelve billion, one hundred four million, three hundred forty-two thousand, one hundred fourteen".
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