Base | Representation |
---|---|
bin | 111000010111101001… |
… | …0010011010111000111 |
3 | 102120110100110122110001 |
4 | 1300233102103113013 |
5 | 3440403404130320 |
6 | 131335525142131 |
7 | 11513535343012 |
oct | 1605722232707 |
9 | 376410418401 |
10 | 121052411335 |
11 | 47379a26359 |
12 | 1b56425a947 |
13 | b55224537b |
14 | 5c05018379 |
15 | 323758b20a |
hex | 1c2f4935c7 |
121052411335 has 4 divisors (see below), whose sum is σ = 145262893608. Its totient is φ = 96841929064.
The previous prime is 121052411281. The next prime is 121052411353. The reversal of 121052411335 is 533114250121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 533114250121 = 3607 ⋅147799903.
It is a cyclic number.
It is not a de Polignac number, because 121052411335 - 229 = 120515540423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12105241129 + ... + 12105241138.
It is an arithmetic number, because the mean of its divisors is an integer number (36315723402).
Almost surely, 2121052411335 is an apocalyptic number.
121052411335 is a deficient number, since it is larger than the sum of its proper divisors (24210482273).
121052411335 is an equidigital number, since it uses as much as digits as its factorization.
121052411335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24210482272.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 121052411335 its reverse (533114250121), we get a palindrome (654166661456).
The spelling of 121052411335 in words is "one hundred twenty-one billion, fifty-two million, four hundred eleven thousand, three hundred thirty-five".
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