12110001220113 has 4 divisors (see below), whose sum is σ = 16146668293488. Its totient is φ = 8073334146740.

The previous prime is 12110001220049. The next prime is 12110001220139. The reversal of 12110001220113 is 31102210001121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12110001220113 - 2⁶ = 12110001220049 is a prime.

It is a super-2 number, since 2×12110001220113² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12110001220092 and 12110001220101.

It is not an unprimeable number, because it can be changed into a prime (12110001220153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018333536683 + ... + 2018333536688.

It is an arithmetic number, because the mean of its divisors is an integer number (4036667073372).

Almost surely, 2^{12110001220113} is an apocalyptic number.

It is an amenable number.

12110001220113 is a deficient number, since it is larger than the sum of its proper divisors (4036667073375).

12110001220113 is an equidigital number, since it uses as much as digits as its factorization.

12110001220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4036667073374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 12110001220113 its reverse (31102210001121), we get a palindrome (43212211221234).

The spelling of 12110001220113 in words is "twelve trillion, one hundred ten billion, one million, two hundred twenty thousand, one hundred thirteen".