12110010201211 has 4 divisors (see below), whose sum is σ = 13041549447472. Its totient is φ = 11178470954952.

The previous prime is 12110010201187. The next prime is 12110010201251. The reversal of 12110010201211 is 11210201001121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12110010201211 - 2¹³ = 12110010193019 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 931539246247 = 12110010201211 / (1 + 2 + 1 + 1 + 0 + 0 + 1 + 0 + 2 + 0 + 1 + 2 + 1 + 1).

It is a junction number, because it is equal to n+sod(n) for n = 12110010201191 and 12110010201200.

It is not an unprimeable number, because it can be changed into a prime (12110010201251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465769623111 + ... + 465769623136.

It is an arithmetic number, because the mean of its divisors is an integer number (3260387361868).

Almost surely, 2^{12110010201211} is an apocalyptic number.

12110010201211 is a deficient number, since it is larger than the sum of its proper divisors (931539246261).

12110010201211 is an equidigital number, since it uses as much as digits as its factorization.

12110010201211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 931539246260.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 12110010201211 its reverse (11210201001121), we get a palindrome (23320211202332).

The spelling of 12110010201211 in words is "twelve trillion, one hundred ten billion, ten million, two hundred one thousand, two hundred eleven".