12110013300013 has 4 divisors (see below), whose sum is σ = 12500658890368. Its totient is φ = 11719367709660.

The previous prime is 12110013300001. The next prime is 12110013300113. The reversal of 12110013300013 is 31000331001121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12110013300013 - 2¹³ = 12110013291821 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12110013300013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12110013300113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195322795131 + ... + 195322795192.

It is an arithmetic number, because the mean of its divisors is an integer number (3125164722592).

Almost surely, 2^{12110013300013} is an apocalyptic number.

It is an amenable number.

12110013300013 is a deficient number, since it is larger than the sum of its proper divisors (390645590355).

12110013300013 is an equidigital number, since it uses as much as digits as its factorization.

12110013300013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 390645590354.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 12110013300013 its reverse (31000331001121), we get a palindrome (43110344301134).

The spelling of 12110013300013 in words is "twelve trillion, one hundred ten billion, thirteen million, three hundred thousand, thirteen".