121100343343431 has 8 divisors (see below), whose sum is σ = 161852487525120. Its totient is φ = 80540880695352.

The previous prime is 121100343343367. The next prime is 121100343343433. The reversal of 121100343343431 is 134343343001121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 121100343343431 - 2⁶ = 121100343343367 is a prime.

It is a super-2 number, since 2×121100343343431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121100343343392 and 121100343343401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121100343343433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48170381935 + ... + 48170384448.

It is an arithmetic number, because the mean of its divisors is an integer number (20231560940640).

Almost surely, 2^{121100343343431} is an apocalyptic number.

121100343343431 is a deficient number, since it is larger than the sum of its proper divisors (40752144181689).

121100343343431 is an equidigital number, since it uses as much as digits as its factorization.

121100343343431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96340766805.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 121100343343431 its reverse (134343343001121), we get a palindrome (255443686344552).

The spelling of 121100343343431 in words is "one hundred twenty-one trillion, one hundred billion, three hundred forty-three million, three hundred forty-three thousand, four hundred thirty-one".