121101201012113 has 4 divisors (see below), whose sum is σ = 138401372585280. Its totient is φ = 103801029438948.

The previous prime is 121101201012089. The next prime is 121101201012149. The reversal of 121101201012113 is 311210102101121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121101201012113 - 2²⁰ = 121101199963537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121101201012091 and 121101201012100.

It is not an unprimeable number, because it can be changed into a prime (121101201012613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8650085786573 + ... + 8650085786586.

It is an arithmetic number, because the mean of its divisors is an integer number (34600343146320).

Almost surely, 2^{121101201012113} is an apocalyptic number.

It is an amenable number.

121101201012113 is a deficient number, since it is larger than the sum of its proper divisors (17300171573167).

121101201012113 is an equidigital number, since it uses as much as digits as its factorization.

121101201012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17300171573166.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 121101201012113 its reverse (311210102101121), we get a palindrome (432311303113234).

The spelling of 121101201012113 in words is "one hundred twenty-one trillion, one hundred one billion, two hundred one million, twelve thousand, one hundred thirteen".