Base | Representation |
---|---|
bin | 11011100010010000011001… |
… | …010101101101101000000001 |
3 | 120212210011200102022011221002 |
4 | 123202100121111231220001 |
5 | 111333111002142002241 |
6 | 1105321102454541345 |
7 | 34336165451215406 |
oct | 3342203125555001 |
9 | 525704612264832 |
10 | 121101323000321 |
11 | 3564a8678019a4 |
12 | 116ba2b8067855 |
13 | 5275a62333b71 |
14 | 21c949a1242ad |
15 | e001cb33b89b |
hex | 6e241956da01 |
121101323000321 has 8 divisors (see below), whose sum is σ = 128225141855784. Its totient is φ = 113977527658240.
The previous prime is 121101323000257. The next prime is 121101323000327. The reversal of 121101323000321 is 123000323101121.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 66509913040321 + 54591409960000 = 8155361^2 + 7388600^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121101323000321 - 26 = 121101323000257 is a prime.
It is a super-2 number, since 2×1211013230003212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121101323000293 and 121101323000302.
It is not an unprimeable number, because it can be changed into a prime (121101323000327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5336591 + ... + 16452411.
It is an arithmetic number, because the mean of its divisors is an integer number (16028142731973).
Almost surely, 2121101323000321 is an apocalyptic number.
It is an amenable number.
121101323000321 is a deficient number, since it is larger than the sum of its proper divisors (7123818855463).
121101323000321 is a wasteful number, since it uses less digits than its factorization.
121101323000321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11756691.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 121101323000321 its reverse (123000323101121), we get a palindrome (244101646101442).
The spelling of 121101323000321 in words is "one hundred twenty-one trillion, one hundred one billion, three hundred twenty-three million, three hundred twenty-one", and thus it is an aban number.
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