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12110220112100 = 22521119289342659
BaseRepresentation
bin1011000000111010000101…
…0111100011000011100100
31120212201121001122221012112
42300032201113203003210
53041403212322041400
641431205221340152
72356635354344135
oct260164127430344
946781531587175
1012110220112100
113949a085a4440
121437060267658
1369acb1696226
142dc1d00dbc8c
151600344e6835
hexb03a15e30e4

12110220112100 has 216 divisors, whose sum is σ = 30596508885600. Its totient is φ = 4125054067200.

The previous prime is 12110220112073. The next prime is 12110220112103. The reversal of 12110220112100 is 121102201121.

It is a super-2 number, since 2×121102201121002 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12110220112103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 35170571 + ... + 35513229.

It is an arithmetic number, because the mean of its divisors is an integer number (141650504100).

Almost surely, 212110220112100 is an apocalyptic number.

12110220112100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12110220112100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15298254442800).

12110220112100 is an abundant number, since it is smaller than the sum of its proper divisors (18486288773500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12110220112100 is a wasteful number, since it uses less digits than its factorization.

12110220112100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 342811 (or 342785 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 12110220112100 its reverse (121102201121), we get a palindrome (12231322313221).

12110220112100 divided by its reverse (121102201121) gives a square (100 = 102).

It can be divided in two parts, 121102 and 20112100, that added together give a palindrome (20233202).

The spelling of 12110220112100 in words is "twelve trillion, one hundred ten billion, two hundred twenty million, one hundred twelve thousand, one hundred".