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12110313055 = 52422062611
BaseRepresentation
bin10110100011101010…
…01011011001011111
31011020222200122102011
423101311023121133
5144300220004210
65321410012051
7606050651101
oct132165133137
934228618364
1012110313055
115154a57495
12241b877027
1311acc79519
1482c535571
154ad2b0d8a
hex2d1d4b65f

12110313055 has 4 divisors (see below), whose sum is σ = 14532375672. Its totient is φ = 9688250440.

The previous prime is 12110313023. The next prime is 12110313071. The reversal of 12110313055 is 55031301121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55031301121 = 439125356039.

It is not a de Polignac number, because 12110313055 - 25 = 12110313023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1211031301 + ... + 1211031310.

It is an arithmetic number, because the mean of its divisors is an integer number (3633093918).

Almost surely, 212110313055 is an apocalyptic number.

12110313055 is a deficient number, since it is larger than the sum of its proper divisors (2422062617).

12110313055 is an equidigital number, since it uses as much as digits as its factorization.

12110313055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2422062616.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 12110313055 its reverse (55031301121), we get a palindrome (67141614176).

The spelling of 12110313055 in words is "twelve billion, one hundred ten million, three hundred thirteen thousand, fifty-five".

Divisors: 1 5 2422062611 12110313055