Base | Representation |
---|---|
bin | 10110100011101010… |
… | …01011011001011111 |
3 | 1011020222200122102011 |
4 | 23101311023121133 |
5 | 144300220004210 |
6 | 5321410012051 |
7 | 606050651101 |
oct | 132165133137 |
9 | 34228618364 |
10 | 12110313055 |
11 | 5154a57495 |
12 | 241b877027 |
13 | 11acc79519 |
14 | 82c535571 |
15 | 4ad2b0d8a |
hex | 2d1d4b65f |
12110313055 has 4 divisors (see below), whose sum is σ = 14532375672. Its totient is φ = 9688250440.
The previous prime is 12110313023. The next prime is 12110313071. The reversal of 12110313055 is 55031301121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55031301121 = 439 ⋅125356039.
It is not a de Polignac number, because 12110313055 - 25 = 12110313023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1211031301 + ... + 1211031310.
It is an arithmetic number, because the mean of its divisors is an integer number (3633093918).
Almost surely, 212110313055 is an apocalyptic number.
12110313055 is a deficient number, since it is larger than the sum of its proper divisors (2422062617).
12110313055 is an equidigital number, since it uses as much as digits as its factorization.
12110313055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2422062616.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 12110313055 its reverse (55031301121), we get a palindrome (67141614176).
The spelling of 12110313055 in words is "twelve billion, one hundred ten million, three hundred thirteen thousand, fifty-five".
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