12110314303 has 4 divisors (see below), whose sum is σ = 12110627200. Its totient is φ = 12110001408.

The previous prime is 12110314261. The next prime is 12110314313. The reversal of 12110314303 is 30341301121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30341301121 = 10163 ⋅2985467.

It is a cyclic number.

It is not a de Polignac number, because 12110314303 - 2³³ = 3520379711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12110314313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88578 + ... + 179071.

It is an arithmetic number, because the mean of its divisors is an integer number (3027656800).

Almost surely, 2^12110314303 is an apocalyptic number.

12110314303 is a deficient number, since it is larger than the sum of its proper divisors (312897).

12110314303 is an equidigital number, since it uses as much as digits as its factorization.

12110314303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312896.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12110314303 its reverse (30341301121), we get a palindrome (42451615424).

The spelling of 12110314303 in words is "twelve billion, one hundred ten million, three hundred fourteen thousand, three hundred three".