12110333231401 has 4 divisors (see below), whose sum is σ = 12110930202112. Its totient is φ = 12109736260692.

The previous prime is 12110333231371. The next prime is 12110333231411. The reversal of 12110333231401 is 10413233301121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12110333231401 - 2³¹ = 12108185747753 is a prime.

It is a super-2 number, since 2×12110333231401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12110333231411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298454925 + ... + 298495498.

It is an arithmetic number, because the mean of its divisors is an integer number (3027732550528).

Almost surely, 2^{12110333231401} is an apocalyptic number.

It is an amenable number.

12110333231401 is a deficient number, since it is larger than the sum of its proper divisors (596970711).

12110333231401 is an equidigital number, since it uses as much as digits as its factorization.

12110333231401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 596970710.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12110333231401 its reverse (10413233301121), we get a palindrome (22523566532522).

The spelling of 12110333231401 in words is "twelve trillion, one hundred ten billion, three hundred thirty-three million, two hundred thirty-one thousand, four hundred one".