Base | Representation |
---|---|
bin | 10110100011101011… |
… | …01011011000001010 |
3 | 1011020222221022002112 |
4 | 23101311223120022 |
5 | 144300233202132 |
6 | 5321412502322 |
7 | 606052035014 |
oct | 132165533012 |
9 | 34228838075 |
10 | 12110444042 |
11 | 5155036944 |
12 | 241b91a9a2 |
13 | 11accc4028 |
14 | 82c56b1b4 |
15 | 4ad2d9ab2 |
hex | 2d1d6b60a |
12110444042 has 4 divisors (see below), whose sum is σ = 18165666066. Its totient is φ = 6055222020.
The previous prime is 12110444033. The next prime is 12110444057. The reversal of 12110444042 is 24044401121.
12110444042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24044401121 = 13 ⋅1849569317.
It can be written as a sum of positive squares in only one way, i.e., 11027310121 + 1083133921 = 105011^2 + 32911^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12110443999 and 12110444017.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3027611009 + ... + 3027611012.
Almost surely, 212110444042 is an apocalyptic number.
12110444042 is a deficient number, since it is larger than the sum of its proper divisors (6055222024).
12110444042 is an equidigital number, since it uses as much as digits as its factorization.
12110444042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6055222023.
The product of its (nonzero) digits is 1024, while the sum is 23.
Adding to 12110444042 its reverse (24044401121), we get a palindrome (36154845163).
The spelling of 12110444042 in words is "twelve billion, one hundred ten million, four hundred forty-four thousand, forty-two".
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