Base | Representation |
---|---|
bin | 111000011001010111… |
… | …0011100011001100011 |
3 | 102120121101001112220022 |
4 | 1300302232130121203 |
5 | 3441013142320120 |
6 | 131345350104055 |
7 | 11515136014652 |
oct | 1606256343143 |
9 | 376541045808 |
10 | 121110120035 |
11 | 473a95617a3 |
12 | 1b57b64b02b |
13 | b56119c428 |
14 | 5c0c95b199 |
15 | 323c68a025 |
hex | 1c32b9c663 |
121110120035 has 16 divisors (see below), whose sum is σ = 145849896192. Its totient is φ = 96543122400.
The previous prime is 121110120007. The next prime is 121110120049. The reversal of 121110120035 is 530021011121.
It is not a de Polignac number, because 121110120035 - 226 = 121043011171 is a prime.
It is a super-2 number, since 2×1211101200352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121110119995 and 121110120022.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6024050 + ... + 6044120.
It is an arithmetic number, because the mean of its divisors is an integer number (9115618512).
Almost surely, 2121110120035 is an apocalyptic number.
121110120035 is a deficient number, since it is larger than the sum of its proper divisors (24739776157).
121110120035 is a wasteful number, since it uses less digits than its factorization.
121110120035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24314.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 121110120035 its reverse (530021011121), we get a palindrome (651131131156).
The spelling of 121110120035 in words is "one hundred twenty-one billion, one hundred ten million, one hundred twenty thousand, thirty-five".
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