Base | Representation |
---|---|
bin | 11101110111010100111000… |
… | …111011111001001111110111 |
3 | 122020001111022021120201112111 |
4 | 131313110320323321033313 |
5 | 114203430234111312210 |
6 | 1143203115411431451 |
7 | 36444250135001023 |
oct | 3567247073711767 |
9 | 566044267521474 |
10 | 131345350104055 |
11 | 3893a282a7085a |
12 | 12893737bb5587 |
13 | 5839a75c82109 |
14 | 24612126ad383 |
15 | 102b8d9a1688a |
hex | 777538ef93f7 |
131345350104055 has 16 divisors (see below), whose sum is σ = 161091307584000. Its totient is φ = 102776254146720.
The previous prime is 131345350104047. The next prime is 131345350104107. The reversal of 131345350104055 is 550401053543131.
It is not a de Polignac number, because 131345350104055 - 23 = 131345350104047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131345350103999 and 131345350104017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1118630931 + ... + 1118748340.
It is an arithmetic number, because the mean of its divisors is an integer number (10068206724000).
Almost surely, 2131345350104055 is an apocalyptic number.
131345350104055 is a deficient number, since it is larger than the sum of its proper divisors (29745957479945).
131345350104055 is a wasteful number, since it uses less digits than its factorization.
131345350104055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2237379534.
The product of its (nonzero) digits is 270000, while the sum is 40.
The spelling of 131345350104055 in words is "one hundred thirty-one trillion, three hundred forty-five billion, three hundred fifty million, one hundred four thousand, fifty-five".
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