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121111111020122 = 260555555510061
BaseRepresentation
bin11011100010011001100000…
…110000000010111001011010
3120212211002221120012002212222
4123202121200300002321122
5111333241023410120442
61105325402030104042
734336663143055316
oct3342314060027132
9525732846162788
10121111111020122
1135653a2a8a1063
121170018a04b022
135276962131062
1421c9b48066b46
15e005a07c58d2
hex6e2660c02e5a

121111111020122 has 4 divisors (see below), whose sum is σ = 181666666530186. Its totient is φ = 60555555510060.

The previous prime is 121111111020037. The next prime is 121111111020143. The reversal of 121111111020122 is 221020111111121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 85057439030281 + 36053671989841 = 9222659^2 + 6004471^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 121111111020122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30277777755029 + ... + 30277777755032.

Almost surely, 2121111111020122 is an apocalyptic number.

121111111020122 is a deficient number, since it is larger than the sum of its proper divisors (60555555510064).

121111111020122 is an equidigital number, since it uses as much as digits as its factorization.

121111111020122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60555555510063.

The product of its (nonzero) digits is 16, while the sum is 17.

Adding to 121111111020122 its reverse (221020111111121), we get a palindrome (342131222131243).

Subtracting 121111111020122 from its reverse (221020111111121), we obtain a palindrome (99909000090999).

The spelling of 121111111020122 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred eleven million, twenty thousand, one hundred twenty-two".

Divisors: 1 2 60555555510061 121111111020122