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121113300131 = 971248590723
BaseRepresentation
bin111000011001011101…
…0100100110010100011
3102120121121001010011122
41300302322210302203
53441020001101011
6131345542202455
711515205031245
oct1606272446243
9376547033148
10121113300131
1147400333a7a
121b58072342b
13b561a43a45
145c0d148095
15323cab73db
hex1c32ea4ca3

121113300131 has 4 divisors (see below), whose sum is σ = 122361890952. Its totient is φ = 119864709312.

The previous prime is 121113300101. The next prime is 121113300137. The reversal of 121113300131 is 131003311121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121113300131 is a prime.

It is a super-2 number, since 2×1211133001312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121113300137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 624295265 + ... + 624295458.

It is an arithmetic number, because the mean of its divisors is an integer number (30590472738).

Almost surely, 2121113300131 is an apocalyptic number.

121113300131 is a deficient number, since it is larger than the sum of its proper divisors (1248590821).

121113300131 is an equidigital number, since it uses as much as digits as its factorization.

121113300131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1248590820.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 121113300131 its reverse (131003311121), we get a palindrome (252116611252).

The spelling of 121113300131 in words is "one hundred twenty-one billion, one hundred thirteen million, three hundred thousand, one hundred thirty-one".

Divisors: 1 97 1248590723 121113300131