121113400333 has 4 divisors (see below), whose sum is σ = 121116404800. Its totient is φ = 121110395868.

The previous prime is 121113400327. The next prime is 121113400351. The reversal of 121113400333 is 333004311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121113400333 - 2⁵ = 121113400301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121113400313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1440933 + ... + 1522666.

It is an arithmetic number, because the mean of its divisors is an integer number (30279101200).

Almost surely, 2^121113400333 is an apocalyptic number.

It is an amenable number.

121113400333 is a deficient number, since it is larger than the sum of its proper divisors (3004467).

121113400333 is an equidigital number, since it uses as much as digits as its factorization.

121113400333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3004466.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 121113400333 its reverse (333004311121), we get a palindrome (454117711454).

The spelling of 121113400333 in words is "one hundred twenty-one billion, one hundred thirteen million, four hundred thousand, three hundred thirty-three".