121114433141 has 4 divisors (see below), whose sum is σ = 130430928012. Its totient is φ = 111797938272.

The previous prime is 121114433113. The next prime is 121114433147. The reversal of 121114433141 is 141334411121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10418489041 + 110695944100 = 102071^2 + 332710^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121114433141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121114433141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121114433147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4658247416 + ... + 4658247441.

It is an arithmetic number, because the mean of its divisors is an integer number (32607732003).

Almost surely, 2^121114433141 is an apocalyptic number.

It is an amenable number.

121114433141 is a deficient number, since it is larger than the sum of its proper divisors (9316494871).

121114433141 is an equidigital number, since it uses as much as digits as its factorization.

121114433141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9316494870.

The product of its digits is 1152, while the sum is 26.

Adding to 121114433141 its reverse (141334411121), we get a palindrome (262448844262).

The spelling of 121114433141 in words is "one hundred twenty-one billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred forty-one".