Base | Representation |
---|---|
bin | 10001101000000001001… |
… | …010111110001111000100 |
3 | 11021210022122021221220212 |
4 | 101220001022332033010 |
5 | 124321014302243134 |
6 | 2324230124414552 |
7 | 153335450536652 |
oct | 21500112761704 |
9 | 4253278257825 |
10 | 1211200431044 |
11 | 42773808177a |
12 | 1768a46a7458 |
13 | 8a2a5bba8b6 |
14 | 4289dc8ddd2 |
15 | 2178d16bbce |
hex | 11a012be3c4 |
1211200431044 has 6 divisors (see below), whose sum is σ = 2119600754334. Its totient is φ = 605600215520.
The previous prime is 1211200431019. The next prime is 1211200431047. The reversal of 1211200431044 is 4401340021121.
It can be written as a sum of positive squares in only one way, i.e., 1124104616644 + 87095814400 = 1060238^2 + 295120^2 .
It is a super-2 number, since 2×12112004310442 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1211200431047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 151400053877 + ... + 151400053884.
It is an arithmetic number, because the mean of its divisors is an integer number (353266792389).
Almost surely, 21211200431044 is an apocalyptic number.
It is an amenable number.
1211200431044 is a deficient number, since it is larger than the sum of its proper divisors (908400323290).
1211200431044 is a wasteful number, since it uses less digits than its factorization.
1211200431044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302800107765 (or 302800107763 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1211200431044 its reverse (4401340021121), we get a palindrome (5612540452165).
The spelling of 1211200431044 in words is "one trillion, two hundred eleven billion, two hundred million, four hundred thirty-one thousand, forty-four".
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