12112064141 has 4 divisors (see below), whose sum is σ = 12120018432. Its totient is φ = 12104109852.

The previous prime is 12112064131. The next prime is 12112064143. The reversal of 12112064141 is 14146021121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112064141 is a prime.

It is a super-3 number, since 3×12112064141³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12112064143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3974861 + ... + 3977906.

It is an arithmetic number, because the mean of its divisors is an integer number (3030004608).

Almost surely, 2^12112064141 is an apocalyptic number.

It is an amenable number.

12112064141 is a deficient number, since it is larger than the sum of its proper divisors (7954291).

12112064141 is an equidigital number, since it uses as much as digits as its factorization.

12112064141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7954290.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 12112064141 its reverse (14146021121), we get a palindrome (26258085262).

The spelling of 12112064141 in words is "twelve billion, one hundred twelve million, sixty-four thousand, one hundred forty-one".