1211223012019 has 4 divisors (see below), whose sum is σ = 1226554948960. Its totient is φ = 1195891075080.

The previous prime is 1211223011959. The next prime is 1211223012029. The reversal of 1211223012019 is 9102103221121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211223012019 - 2³³ = 1202633077427 is a prime.

It is a super-2 number, since 2×1211223012019² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211223011984 and 1211223012002.

It is not an unprimeable number, because it can be changed into a prime (1211223012029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7665968352 + ... + 7665968509.

It is an arithmetic number, because the mean of its divisors is an integer number (306638737240).

Almost surely, 2^{1211223012019} is an apocalyptic number.

1211223012019 is a deficient number, since it is larger than the sum of its proper divisors (15331936941).

1211223012019 is an equidigital number, since it uses as much as digits as its factorization.

1211223012019 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15331936940.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 1211223012019 in words is "one trillion, two hundred eleven billion, two hundred twenty-three million, twelve thousand, nineteen".