Base | Representation |
---|---|
bin | 1011000001000001110101… |
… | …1010110001011000111111 |
3 | 1120212220222002211212020012 |
4 | 2300100131122301120333 |
5 | 3041421443120111111 |
6 | 41432151525213435 |
7 | 2360041055412545 |
oct | 260203532613077 |
9 | 46786862755205 |
10 | 12112301332031 |
11 | 394a88637580a |
12 | 143754126127b |
13 | 69b25390a004 |
14 | 2dc34a699d95 |
15 | 16010709e48b |
hex | b041d6b163f |
12112301332031 has 8 divisors (see below), whose sum is σ = 12128438665200. Its totient is φ = 12096168671808.
The previous prime is 12112301331971. The next prime is 12112301332037. The reversal of 12112301332031 is 13023310321121.
12112301332031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12112301332031 - 210 = 12112301331007 is a prime.
It is a super-2 number, since 2×121123013320312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12112301331988 and 12112301332006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12112301332037) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4034645 + ... + 6364193.
It is an arithmetic number, because the mean of its divisors is an integer number (1516054833150).
Almost surely, 212112301332031 is an apocalyptic number.
12112301332031 is a deficient number, since it is larger than the sum of its proper divisors (16137333169).
12112301332031 is an equidigital number, since it uses as much as digits as its factorization.
12112301332031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2336473.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12112301332031 its reverse (13023310321121), we get a palindrome (25135611653152).
The spelling of 12112301332031 in words is "twelve trillion, one hundred twelve billion, three hundred one million, three hundred thirty-two thousand, thirty-one".
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