Base | Representation |
---|---|
bin | 1011000001000001110110… |
… | …0001010000101010101011 |
3 | 1120212220222020001021112011 |
4 | 2300100131201100222223 |
5 | 3041421444034024003 |
6 | 41432152025500351 |
7 | 2360041106025625 |
oct | 260203541205253 |
9 | 46786866037464 |
10 | 12112303033003 |
11 | 394a887327778 |
12 | 14375419416b7 |
13 | 69b2540842c4 |
14 | 2dc34a9bdc15 |
15 | 1601072d846d |
hex | b041d850aab |
12112303033003 has 4 divisors (see below), whose sum is σ = 12265623324640. Its totient is φ = 11958982741368.
The previous prime is 12112303032967. The next prime is 12112303033009. The reversal of 12112303033003 is 30033030321121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12112303033003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12112303033009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76660145700 + ... + 76660145857.
It is an arithmetic number, because the mean of its divisors is an integer number (3066405831160).
Almost surely, 212112303033003 is an apocalyptic number.
12112303033003 is a deficient number, since it is larger than the sum of its proper divisors (153320291637).
12112303033003 is an equidigital number, since it uses as much as digits as its factorization.
12112303033003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153320291636.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 12112303033003 its reverse (30033030321121), we get a palindrome (42145333354124).
The spelling of 12112303033003 in words is "twelve trillion, one hundred twelve billion, three hundred three million, thirty-three thousand, three".
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