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1211231122013 = 11110111920183
BaseRepresentation
bin10001101000000011000…
…000000011001001011101
311021210101210001020000102
4101220003000003021131
5124321100131401023
62324233142310445
7153336302444003
oct21500300031135
94253353036012
101211231122013
11427753434310
121768b2a28425
138a2ac375233
14428a3d9ca73
1521790bd0628
hex11a0300325d

1211231122013 has 4 divisors (see below), whose sum is σ = 1321343042208. Its totient is φ = 1101119201820.

The previous prime is 1211231121941. The next prime is 1211231122033. The reversal of 1211231122013 is 3102211321121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1211231122013 - 210 = 1211231120989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211231122033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55055960081 + ... + 55055960102.

It is an arithmetic number, because the mean of its divisors is an integer number (330335760552).

Almost surely, 21211231122013 is an apocalyptic number.

It is an amenable number.

1211231122013 is a deficient number, since it is larger than the sum of its proper divisors (110111920195).

1211231122013 is a wasteful number, since it uses less digits than its factorization.

1211231122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110111920194.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1211231122013 its reverse (3102211321121), we get a palindrome (4313442443134).

The spelling of 1211231122013 in words is "one trillion, two hundred eleven billion, two hundred thirty-one million, one hundred twenty-two thousand, thirteen".

Divisors: 1 11 110111920183 1211231122013