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12113002023210 = 232511431132518081
BaseRepresentation
bin1011000001000100011100…
…1011101100100100101010
31120212222202221022122211100
42300101013023230210222
53041424412004220320
641432345235342230
72360064324243144
oct260210713544452
946788687278740
1012113002023210
113950105947430
1214376b7a51976
1369b335b2bb8a
142dc3b5773c94
1516014885b790
hexb04472ec92a

12113002023210 has 192 divisors, whose sum is σ = 35467003668096. Its totient is φ = 2842811596800.

The previous prime is 12113002023181. The next prime is 12113002023319. The reversal of 12113002023210 is 1232020031121.

12113002023210 is a `hidden beast` number, since 1 + 21 + 1 + 300 + 20 + 2 + 321 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3551370 + ... + 6069450.

It is an arithmetic number, because the mean of its divisors is an integer number (184723977438).

Almost surely, 212113002023210 is an apocalyptic number.

12113002023210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113002023210, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17733501834048).

12113002023210 is an abundant number, since it is smaller than the sum of its proper divisors (23354001644886).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113002023210 is a wasteful number, since it uses less digits than its factorization.

12113002023210 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2518261 (or 2518258 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12113002023210 its reverse (1232020031121), we get a palindrome (13345022054331).

The spelling of 12113002023210 in words is "twelve trillion, one hundred thirteen billion, two million, twenty-three thousand, two hundred ten".