121130343129 has 4 divisors (see below), whose sum is σ = 161507124176. Its totient is φ = 80753562084.

The previous prime is 121130343101. The next prime is 121130343227. The reversal of 121130343129 is 921343031121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121130343129 - 2¹⁵ = 121130310361 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121130343096 and 121130343105.

It is not an unprimeable number, because it can be changed into a prime (121130344129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20188390519 + ... + 20188390524.

It is an arithmetic number, because the mean of its divisors is an integer number (40376781044).

Almost surely, 2^121130343129 is an apocalyptic number.

It is an amenable number.

121130343129 is a deficient number, since it is larger than the sum of its proper divisors (40376781047).

121130343129 is an equidigital number, since it uses as much as digits as its factorization.

121130343129 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40376781046.

The product of its (nonzero) digits is 3888, while the sum is 30.

The spelling of 121130343129 in words is "one hundred twenty-one billion, one hundred thirty million, three hundred forty-three thousand, one hundred twenty-nine".