12113101020223 has 4 divisors (see below), whose sum is σ = 13843544023120. Its totient is φ = 10382658017328.

The previous prime is 12113101020203. The next prime is 12113101020269. The reversal of 12113101020223 is 32202010131121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113101020223 - 2⁵ = 12113101020191 is a prime.

It is a super-2 number, since 2×12113101020223² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12113101020223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113101020203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865221501438 + ... + 865221501451.

It is an arithmetic number, because the mean of its divisors is an integer number (3460886005780).

Almost surely, 2^{12113101020223} is an apocalyptic number.

12113101020223 is a deficient number, since it is larger than the sum of its proper divisors (1730443002897).

12113101020223 is an equidigital number, since it uses as much as digits as its factorization.

12113101020223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1730443002896.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12113101020223 its reverse (32202010131121), we get a palindrome (44315111151344).

The spelling of 12113101020223 in words is "twelve trillion, one hundred thirteen billion, one hundred one million, twenty thousand, two hundred twenty-three".