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1211311330031 = 11591866427319
BaseRepresentation
bin10001101000000111110…
…010000001001011101111
311021210121100222012201202
4101220013302001023233
5124321231200030111
62324245125400115
7153341265264425
oct21500762011357
94253540865652
101211311330031
11427794737830
1217691586903b
138a2c2b791ba
14428b08bb115
1521797c75b3b
hex11a07c812ef

1211311330031 has 8 divisors (see below), whose sum is σ = 1343827670400. Its totient is φ = 1082527844440.

The previous prime is 1211311330001. The next prime is 1211311330063. The reversal of 1211311330031 is 1300331131121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1211311330031 - 230 = 1210237588207 is a prime.

It is a super-2 number, since 2×12113113300312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211311329985 and 1211311330012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211311330001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 933213011 + ... + 933214308.

It is an arithmetic number, because the mean of its divisors is an integer number (167978458800).

Almost surely, 21211311330031 is an apocalyptic number.

1211311330031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1211311330031 is a deficient number, since it is larger than the sum of its proper divisors (132516340369).

1211311330031 is a wasteful number, since it uses less digits than its factorization.

1211311330031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1866427389.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1211311330031 its reverse (1300331131121), we get a palindrome (2511642461152).

The spelling of 1211311330031 in words is "one trillion, two hundred eleven billion, three hundred eleven million, three hundred thirty thousand, thirty-one".

Divisors: 1 11 59 649 1866427319 20530700509 110119211821 1211311330031