Base | Representation |
---|---|
bin | 1011000001000100110111… |
… | …1000011101101011110011 |
3 | 1120220000001202211002222121 |
4 | 2300101031320131223303 |
5 | 3041430124243001003 |
6 | 41432404332415111 |
7 | 2360100160515340 |
oct | 260211570355363 |
9 | 46800052732877 |
10 | 12113114422003 |
11 | 39501633372a1 |
12 | 1437729617497 |
13 | 69b3531c403a |
14 | 2dc3c66717c7 |
15 | 16015365ecbd |
hex | b044de1daf3 |
12113114422003 has 4 divisors (see below), whose sum is σ = 13843559339440. Its totient is φ = 10382669504568.
The previous prime is 12113114421949. The next prime is 12113114422033. The reversal of 12113114422003 is 30022441131121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12113114422003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12113114422033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865222458708 + ... + 865222458721.
It is an arithmetic number, because the mean of its divisors is an integer number (3460889834860).
Almost surely, 212113114422003 is an apocalyptic number.
12113114422003 is a deficient number, since it is larger than the sum of its proper divisors (1730444917437).
12113114422003 is an equidigital number, since it uses as much as digits as its factorization.
12113114422003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1730444917436.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 12113114422003 its reverse (30022441131121), we get a palindrome (42135555553124).
The spelling of 12113114422003 in words is "twelve trillion, one hundred thirteen billion, one hundred fourteen million, four hundred twenty-two thousand, three".
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