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12113115 = 357115363
BaseRepresentation
bin101110001101…
…010011011011
3211210102001220
4232031103123
511100104430
61111343123
7204650130
oct56152333
924712056
1012113115
116923843
124081aa3
132681631
141874587
1510e4110
hexb8d4db

12113115 has 16 divisors (see below), whose sum is σ = 22149888. Its totient is φ = 5537376.

The previous prime is 12113093. The next prime is 12113117. The reversal of 12113115 is 51131121.

12113115 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12113115 - 25 = 12113083 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 12113094 and 12113103.

It is not an unprimeable number, because it can be changed into a prime (12113117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57577 + ... + 57786.

It is an arithmetic number, because the mean of its divisors is an integer number (1384368).

Almost surely, 212113115 is an apocalyptic number.

12113115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12113115 is a deficient number, since it is larger than the sum of its proper divisors (10036773).

12113115 is a wasteful number, since it uses less digits than its factorization.

12113115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115378.

The product of its digits is 30, while the sum is 15.

The square root of 12113115 is about 3480.3900643462. The cubic root of 12113115 is about 229.6599575008.

Adding to 12113115 its reverse (51131121), we get a palindrome (63244236).

The spelling of 12113115 in words is "twelve million, one hundred thirteen thousand, one hundred fifteen".

Divisors: 1 3 5 7 15 21 35 105 115363 346089 576815 807541 1730445 2422623 4037705 12113115