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121131310055112 = 23337432173785711
BaseRepresentation
bin11011100010101100010100…
…101101001111111011001000
3120212220001002021020101211000
4123202230110231033323020
5111334103410333230422
61105342542225335000
734341306533040210
oct3342542455177310
9525801067211730
10121131310055112
1135661555704005
1211704086797460
135278830b15976
1421cab0295d240
15e00d83c59cac
hex6e2b14b4fec8

121131310055112 has 256 divisors, whose sum is σ = 393509414707200. Its totient is φ = 33802137008640.

The previous prime is 121131310055039. The next prime is 121131310055167. The reversal of 121131310055112 is 211550013131121.

121131310055112 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 3 + 1 + 3 + 100 + 551 + 1 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1413209937 + ... + 1413295647.

It is an arithmetic number, because the mean of its divisors is an integer number (1537146151200).

Almost surely, 2121131310055112 is an apocalyptic number.

121131310055112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121131310055112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196754707353600).

121131310055112 is an abundant number, since it is smaller than the sum of its proper divisors (272378104652088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121131310055112 is a wasteful number, since it uses less digits than its factorization.

121131310055112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107513 (or 107503 counting only the distinct ones).

The product of its (nonzero) digits is 900, while the sum is 27.

Adding to 121131310055112 its reverse (211550013131121), we get a palindrome (332681323186233).

The spelling of 121131310055112 in words is "one hundred twenty-one trillion, one hundred thirty-one billion, three hundred ten million, fifty-five thousand, one hundred twelve".