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1211314034401 = 31731427375101
BaseRepresentation
bin10001101000000111111…
…100010101011011100001
311021210121120001121102121
4101220013330111123201
5124321232343100101
62324245303344241
7153341330260042
oct21500774253341
94253546047377
101211314034401
11427796214649
12176916752081
138a2c35b5113
14428b0dc28c9
152179810c0a1
hex11a07f156e1

1211314034401 has 16 divisors (see below), whose sum is σ = 1268408913408. Its totient is φ = 1155368016000.

The previous prime is 1211314034377. The next prime is 1211314034417. The reversal of 1211314034401 is 1044304131121.

It is a de Polignac number, because none of the positive numbers 2k-1211314034401 is a prime.

It is a super-2 number, since 2×12113140344012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1211314034101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3041751 + ... + 3416851.

It is an arithmetic number, because the mean of its divisors is an integer number (79275557088).

Almost surely, 21211314034401 is an apocalyptic number.

It is an amenable number.

1211314034401 is a deficient number, since it is larger than the sum of its proper divisors (57094879007).

1211314034401 is a wasteful number, since it uses less digits than its factorization.

1211314034401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 376632.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1211314034401 its reverse (1044304131121), we get a palindrome (2255618165522).

The spelling of 1211314034401 in words is "one trillion, two hundred eleven billion, three hundred fourteen million, thirty-four thousand, four hundred one".

Divisors: 1 31 73 1427 2263 44237 104171 375101 3229301 11628131 27382373 535269127 848853563 16593342937 39074646271 1211314034401