Base | Representation |
---|---|
bin | 10001101000001001101… |
… | …000100111100010010010 |
3 | 11021210200112110202022022 |
4 | 101220021220213202102 |
5 | 124321312124420424 |
6 | 2324252200011442 |
7 | 153342123453161 |
oct | 21501150474222 |
9 | 4253615422268 |
10 | 1211342420114 |
11 | 427800242212 |
12 | 176924160b82 |
13 | 8a2c94433b8 |
14 | 428b4a913d8 |
15 | 2179a86795e |
hex | 11a09a27892 |
1211342420114 has 4 divisors (see below), whose sum is σ = 1817013630174. Its totient is φ = 605671210056.
The previous prime is 1211342420077. The next prime is 1211342420117. The reversal of 1211342420114 is 4110242431121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1044825375889 + 166517044225 = 1022167^2 + 408065^2 .
It is not an unprimeable number, because it can be changed into a prime (1211342420117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302835605027 + ... + 302835605030.
Almost surely, 21211342420114 is an apocalyptic number.
1211342420114 is a deficient number, since it is larger than the sum of its proper divisors (605671210060).
1211342420114 is an equidigital number, since it uses as much as digits as its factorization.
1211342420114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605671210059.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 1211342420114 its reverse (4110242431121), we get a palindrome (5321584851235).
The spelling of 1211342420114 in words is "one trillion, two hundred eleven billion, three hundred forty-two million, four hundred twenty thousand, one hundred fourteen".
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