Base | Representation |
---|---|
bin | 10110100100000010… |
… | …00101010111111001 |
3 | 1011021012120012200121 |
4 | 23102001011113321 |
5 | 144302014342410 |
6 | 5322000533241 |
7 | 606116330263 |
oct | 132201052771 |
9 | 34235505617 |
10 | 12113434105 |
11 | 5156799373 |
12 | 2420921221 |
13 | 11b07cccb6 |
14 | 82cb08b33 |
15 | 4ad6ca9da |
hex | 2d20455f9 |
12113434105 has 8 divisors (see below), whose sum is σ = 14542004232. Its totient is φ = 9686825088.
The previous prime is 12113434079. The next prime is 12113434121. The reversal of 12113434105 is 50143431121.
It can be written as a sum of positive squares in 4 ways, for example, as 1644870249 + 10468563856 = 40557^2 + 102316^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12113434105 - 29 = 12113433593 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12113434105.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476652 + ... + 501421.
It is an arithmetic number, because the mean of its divisors is an integer number (1817750529).
Almost surely, 212113434105 is an apocalyptic number.
It is an amenable number.
12113434105 is a deficient number, since it is larger than the sum of its proper divisors (2428570127).
12113434105 is an equidigital number, since it uses as much as digits as its factorization.
12113434105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 980555.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12113434105 its reverse (50143431121), we get a palindrome (62256865226).
The spelling of 12113434105 in words is "twelve billion, one hundred thirteen million, four hundred thirty-four thousand, one hundred five".
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