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12114000434 = 26057000217
BaseRepresentation
bin10110100100000110…
…01111101000110010
31011021020121222112202
423102003033220302
5144302141003214
65322021023202
7606124206344
oct132203175062
934236558482
1012114000434
115157045908
122420b54b02
1311b096a9c3
1482cc15294
154ad78d6de
hex2d20cfa32

12114000434 has 4 divisors (see below), whose sum is σ = 18171000654. Its totient is φ = 6057000216.

The previous prime is 12114000427. The next prime is 12114000439. The reversal of 12114000434 is 43400041121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11978208025 + 135792409 = 109445^2 + 11653^2 .

It is a super-3 number, since 3×121140004343 (a number of 31 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12114000439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3028500107 + ... + 3028500110.

Almost surely, 212114000434 is an apocalyptic number.

12114000434 is a deficient number, since it is larger than the sum of its proper divisors (6057000220).

12114000434 is an equidigital number, since it uses as much as digits as its factorization.

12114000434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6057000219.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 12114000434 its reverse (43400041121), we get a palindrome (55514041555).

The spelling of 12114000434 in words is "twelve billion, one hundred fourteen million, four hundred thirty-four", and thus it is an aban number.

Divisors: 1 2 6057000217 12114000434