Base | Representation |
---|---|
bin | 10110100100000110… |
… | …01111101000110010 |
3 | 1011021020121222112202 |
4 | 23102003033220302 |
5 | 144302141003214 |
6 | 5322021023202 |
7 | 606124206344 |
oct | 132203175062 |
9 | 34236558482 |
10 | 12114000434 |
11 | 5157045908 |
12 | 2420b54b02 |
13 | 11b096a9c3 |
14 | 82cc15294 |
15 | 4ad78d6de |
hex | 2d20cfa32 |
12114000434 has 4 divisors (see below), whose sum is σ = 18171000654. Its totient is φ = 6057000216.
The previous prime is 12114000427. The next prime is 12114000439. The reversal of 12114000434 is 43400041121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11978208025 + 135792409 = 109445^2 + 11653^2 .
It is a super-3 number, since 3×121140004343 (a number of 31 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12114000439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3028500107 + ... + 3028500110.
Almost surely, 212114000434 is an apocalyptic number.
12114000434 is a deficient number, since it is larger than the sum of its proper divisors (6057000220).
12114000434 is an equidigital number, since it uses as much as digits as its factorization.
12114000434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6057000219.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12114000434 its reverse (43400041121), we get a palindrome (55514041555).
The spelling of 12114000434 in words is "twelve billion, one hundred fourteen million, four hundred thirty-four", and thus it is an aban number.
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