12114011041121 has 16 divisors (see below), whose sum is σ = 13270788076608. Its totient is φ = 10966567987200.

The previous prime is 12114011041117. The next prime is 12114011041151.

12114011041121 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 12114011041121 - 2² = 12114011041117 is a prime.

It is a super-3 number, since 3×12114011041121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12114011041093 and 12114011041102.

It is not an unprimeable number, because it can be changed into a prime (12114011041151) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 819521 + ... + 4989953.

It is an arithmetic number, because the mean of its divisors is an integer number (829424254788).

Almost surely, 2^{12114011041121} is an apocalyptic number.

12114011041121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12114011041121 is a deficient number, since it is larger than the sum of its proper divisors (1156777035487).

12114011041121 is a wasteful number, since it uses less digits than its factorization.

12114011041121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4171552.

The product of its (nonzero) digits is 64, while the sum is 20.

It can be divided in two parts, 1211401 and 1041121, that added together give a palindrome (2252522).

The spelling of 12114011041121 in words is "twelve trillion, one hundred fourteen billion, eleven million, forty-one thousand, one hundred twenty-one".