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1211401320314 = 2605700660157
BaseRepresentation
bin10001101000001101001…
…001010011011101111010
311021210211122022012012012
4101220031021103131322
5124321422214222224
62324302102245522
7153343440216653
oct21501511233572
94253748265165
101211401320314
11427830511869
1217693ba268a2
138a3086c68a3
14428bc82452a
15217a0aee80e
hex11a0d25377a

1211401320314 has 4 divisors (see below), whose sum is σ = 1817101980474. Its totient is φ = 605700660156.

The previous prime is 1211401320299. The next prime is 1211401320323. The reversal of 1211401320314 is 4130231041121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1014083238289 + 197318082025 = 1007017^2 + 444205^2 .

It is a super-3 number, since 3×12114013203143 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1211401320314.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302850330077 + ... + 302850330080.

Almost surely, 21211401320314 is an apocalyptic number.

1211401320314 is a deficient number, since it is larger than the sum of its proper divisors (605700660160).

1211401320314 is an equidigital number, since it uses as much as digits as its factorization.

1211401320314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605700660159.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1211401320314 its reverse (4130231041121), we get a palindrome (5341632361435).

The spelling of 1211401320314 in words is "one trillion, two hundred eleven billion, four hundred one million, three hundred twenty thousand, three hundred fourteen".

Divisors: 1 2 605700660157 1211401320314