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12114024402 = 237128436677
BaseRepresentation
bin10110100100000110…
…10101011111010010
31011021020200012102110
423102003111133102
5144302142240102
65322021330150
7606124336254
oct132203253722
934236605373
1012114024402
115157061917
122420b66956
1311b097889c
1482cc1dcd4
154ad79586c
hex2d20d57d2

12114024402 has 16 divisors (see below), whose sum is σ = 24569289792. Its totient is φ = 3981134640.

The previous prime is 12114024397. The next prime is 12114024421. The reversal of 12114024402 is 20442041121.

12114024402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×121140244023 (a number of 31 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14217913 + ... + 14218764.

It is an arithmetic number, because the mean of its divisors is an integer number (1535580612).

Almost surely, 212114024402 is an apocalyptic number.

12114024402 is an abundant number, since it is smaller than the sum of its proper divisors (12455265390).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12114024402 is a wasteful number, since it uses less digits than its factorization.

12114024402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28436753.

The product of its (nonzero) digits is 512, while the sum is 21.

Adding to 12114024402 its reverse (20442041121), we get a palindrome (32556065523).

The spelling of 12114024402 in words is "twelve billion, one hundred fourteen million, twenty-four thousand, four hundred two".

Divisors: 1 2 3 6 71 142 213 426 28436677 56873354 85310031 170620062 2019004067 4038008134 6057012201 12114024402