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12114243301 = 18198368087
BaseRepresentation
bin10110100100001000…
…01010111011100101
31011021021002022200211
423102010022323211
5144302221241201
65322030135421
7606126240406
oct132204127345
934237068624
1012114243301
1151571a1326
122421051571
1311b0a24404
1482cc799ad
154ad7da651
hex2d210aee5

12114243301 has 8 divisors (see below), whose sum is σ = 12193743744. Its totient is φ = 12034881360.

The previous prime is 12114243257. The next prime is 12114243311. The reversal of 12114243301 is 10334241121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12114243301 - 215 = 12114210533 is a prime.

It is a super-3 number, since 3×121142433013 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114243311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143880 + ... + 211966.

It is an arithmetic number, because the mean of its divisors is an integer number (1524217968).

Almost surely, 212114243301 is an apocalyptic number.

It is an amenable number.

12114243301 is a deficient number, since it is larger than the sum of its proper divisors (79500443).

12114243301 is an equidigital number, since it uses as much as digits as its factorization.

12114243301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69251.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12114243301 its reverse (10334241121), we get a palindrome (22448484422).

The spelling of 12114243301 in words is "twelve billion, one hundred fourteen million, two hundred forty-three thousand, three hundred one".

Divisors: 1 181 983 68087 177923 12323747 66929521 12114243301